0.6x^2-2.55x+0.098=0

Solution for 0.6x^2-2.55x+0.098=0 equation:

0.6x^2-2.55x+0.098=0

a = 0.6; b = -2.55; c = +0.098;
Δ = b2-4ac
Δ = -2.552-4·0.6·0.098
Δ = 6.2673
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.55)-\sqrt{6.2673}}{2*0.6}=\frac{2.55-\sqrt{6.2673}}{1.2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.55)+\sqrt{6.2673}}{2*0.6}=\frac{2.55+\sqrt{6.2673}}{1.2}
$